R&R结果的分析
有一份双R分析的报告,不知如何下结论,请资深人士帮我解释一下,先谢谢了.
数据分析结果如下:
Sorting Measuring
s(EV)= 0.0563 Equipment Variation (EV)= 0.2898 14.5% 14.1%
s(AV)= 0.0065 Appraiser Variation (AV)= 0.0332 1.7% 1.6%
s(PV)= 0.3954 Part Variation (PV)= 2.0363
Total Variation (TV)= 2.0570
R&R= 0.291707081 14.6% 14.2%
不清楚sorting和measuring的区别是什么,我该依据那一个值做最终的结论?
数据也贴在这里做参考:
Cat.1: ZJ7068 Cat.2: ZJ60048
part no. value1 value2 value3 value1 value2 value3
1 36.5 36.6 36.5 36.6 36.7 36.7
2 37.2 37.2 37.3 37.2 37.2 37.3
3 37.1 37.1 37.1 37.2 37.2 37.1
4 37.5 37.4 37.4 37.4 37.5 37.4
5 36.7 36.7 36.8 36.8 36.8 36.7
6 36.9 36.9 36.8 36.8 36.8 36.8
7 37.2 37.4 37.2 37.2 37.2 37.2
8 36.5 36.6 36.6 36.7 36.8 36.8
9 37.8 37.8 37.7 37.8 37.8 37.8
10 36.7 36.8 36.8 36.7 36.6 36.6
数据分析结果如下:
Sorting Measuring
s(EV)= 0.0563 Equipment Variation (EV)= 0.2898 14.5% 14.1%
s(AV)= 0.0065 Appraiser Variation (AV)= 0.0332 1.7% 1.6%
s(PV)= 0.3954 Part Variation (PV)= 2.0363
Total Variation (TV)= 2.0570
R&R= 0.291707081 14.6% 14.2%
不清楚sorting和measuring的区别是什么,我该依据那一个值做最终的结论?
数据也贴在这里做参考:
Cat.1: ZJ7068 Cat.2: ZJ60048
part no. value1 value2 value3 value1 value2 value3
1 36.5 36.6 36.5 36.6 36.7 36.7
2 37.2 37.2 37.3 37.2 37.2 37.3
3 37.1 37.1 37.1 37.2 37.2 37.1
4 37.5 37.4 37.4 37.4 37.5 37.4
5 36.7 36.7 36.8 36.8 36.8 36.7
6 36.9 36.9 36.8 36.8 36.8 36.8
7 37.2 37.4 37.2 37.2 37.2 37.2
8 36.5 36.6 36.6 36.7 36.8 36.8
9 37.8 37.8 37.7 37.8 37.8 37.8
10 36.7 36.8 36.8 36.7 36.6 36.6
没有找到相关结果
已邀请:
11 个回复
rocky2003 (威望:1) (上海 浦东) -
赞同来自:
你的解释是正确的,但是<10%是一种很严格的把关标准。应该视情况确定是否可接受<30%的测量系统。